What Tensile Failure Strength Must Material Possess to Avoid Failure?
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required for the information.
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A plate that is 5cm wide and 1 cm thick has a hole that is .25cm in diameter, is subjected to a tensile force of 60N. What is tensile failure strength must material possess to avoid failure? (Plate is made of a brittle material, so Maximum Shear Stress Theory is used, I believe)
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The stress concentration factor for a hole this size in this plate is approximately 2.72, therefore the maximum stress is 0.327 N/mm^2.
The amount of material subject to tensile stress is
(5 -0.25) * 1 cm^2
The tensile stress is thus 60N / (50-2.5)* 10 N/mm^2
I do not see how shear comes into it unless I have misunderstood the question.