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	<title>Comments on: What Tensile Failure Strength Must Material Possess to Avoid Failure?</title>
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	<link>http://www.kigro.com/what-tensile-failure-strength-must-material-possess-to-avoid-failure.html</link>
	<description>Mechanical Engineering Design</description>
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		<title>By: JC</title>
		<link>http://www.kigro.com/what-tensile-failure-strength-must-material-possess-to-avoid-failure.html/comment-page-1#comment-218</link>
		<dc:creator>JC</dc:creator>
		<pubDate>Thu, 03 Dec 2009 10:40:26 +0000</pubDate>
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		<description>The amount of material subject to tensile stress is
(5 -0.25) * 1 cm^2
The tensile stress is thus 60N / (50-2.5)* 10 N/mm^2
I do not see how shear comes into it unless I have misunderstood the question.</description>
		<content:encoded><![CDATA[<p>The amount of material subject to tensile stress is<br />
(5 -0.25) * 1 cm^2<br />
The tensile stress is thus 60N / (50-2.5)* 10 N/mm^2<br />
I do not see how shear comes into it unless I have misunderstood the question.</p>
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		<title>By: D W</title>
		<link>http://www.kigro.com/what-tensile-failure-strength-must-material-possess-to-avoid-failure.html/comment-page-1#comment-217</link>
		<dc:creator>D W</dc:creator>
		<pubDate>Thu, 03 Dec 2009 10:08:21 +0000</pubDate>
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		<description>The stress concentration factor for a hole this size in this plate is approximately 2.72, therefore the maximum stress is 0.327 N/mm^2.</description>
		<content:encoded><![CDATA[<p>The stress concentration factor for a hole this size in this plate is approximately 2.72, therefore the maximum stress is 0.327 N/mm^2.</p>
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